STRUCTURE OF BENZENE
1.
Molecular formula:
The molecular formula of benzene as determined on the basis of chemical analysis
and molecular mass determination is C6H6, and it
corresponds to the general formula CnHn (n=6).
2.
Straight-chain structure not possible:
§ The molecule
suggests a high degree of unsaturation since it has eight hydrogen atoms less
than the alkane corresponding to the formula C6H14.
§ Keeping
in view the tetra-co-valency of carbon, the following open-chain structures can
be suggested.
§ However,
the structures listed above are not in agreement with some of the properties of
benzene.
For
example:
i)
Benzene does not decolorize bromine water as
is done by alkenes & alkynes, i.e., Benzene does not undergo addition
reaction, instead undergo substitution reactions under suitable conditions.
ii)
Alkaline KMnO4 solution (Bayer’s
reagent) does not react with benzene in cold.
iii)
Benzene forms only one kind of
mono-substituted product C6H5X (say X=Cl).
iv)
Benzene forms three kinds of di-substitution
products, C6H4X2 or C6H4XY,
distinguished as ortho - (1, 2), meta - (1, 3) and para – (1, 4) substitution
product.
3.
Ring (cyclic) structure for Benzene:
i)
Benzene gives only one mono-substituted product when subjected to the halogenation.
This
indicates that all the six-carbon, as well as hydrogen atoms in the molecule, are
identical.
ii)
Benzene forms three kinds of di-substitution products, C6H4X2, or C6H4XY.
{Distinguished as ortho - (1, 2), meta - (1, 3) & para - (1, 4)
substitution products.}
§ In
order to account for the above facts, a cyclic or ring structure for benzene
was suggested.
§ A number of structures were suggested by different persons. However, the most accepted structure is by Kekule.
§ In
1865, Kekule (August Kekule) suggested a hexagonal structure for benzene
composed of six carbon atoms joined by alternate single & double bonds and
with one hydrogen atom attached to each one of them.
Evidence
in favor of Kekule’s structure:
i)
It explains the addition of three molecules
of hydrogen, chlorine, and ozone due to the presence of three double bonds.
ii)
It explains the formation of only one
mono-substitution product due to the equivalence of six hydrogen atoms.
iii)
It also explains the formation of
di-substitution products:
iv)
X-ray crystallographic studies of the benzene
show the presence of hexagonal structure.
v)
The synthesis of benzene from three molecules
of acetylene also supports the Kekule structure.







Useful. Sanjeeb once check the ii point in ring structure, it is disubstitution products
ReplyDeleteIt is fantastic
ReplyDeleteIt is very useful to students.
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